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[原创] 新160个CrackMe 007--Reg.exe注册算法分析

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lies2014 发表于 2022-10-5 03:55 回帖奖励
本帖最后由 lies2014 于 2022-10-5 03:59 编辑

    CrackMe程序运行后输入用户名和序列号,提示重启验证。


    如何找到验证Call和真码比较简单,在这里我就不在赘述,大家可以参考以下教程:
    文字教程:https://www.bilibili.com/read/cv18424843
    视频教程:https://www.bilibili.com/video/BV1oa411z7rs

    因为代码看起来比较复杂,上面两个教程都没有对注册算法进行分析。以往我总是满足于能够爆破而不思进取,搞得自己一直没有进步,这次终于国庆节长假有点时间,而某些原因又限制了出行不敢乱跑,终于潜下心来,打算痛改前非,勇攀高峰,刀口向内,自我革命,花了一天时间做了分析,并写下了人生第一个没啥X用的注册机。
    具体的代码分析之前,先讲讲分析过程中个人的一些心得:动态调试是算法分析的一大利器,分析之前先以步过的方式大致的看一下每一个Call的参数及输出结果,有些调用很明显就能看出功能,可以跳过省下不少时间;动态分析目前Windows平台下x64dbg无疑是最好用的工具之一,而且现在很多都是64位的程序,OD已经力不从心了,而x64dbg一直在频繁的改进,我自从用了x64dbg以后就再也没有碰过OD了,早用早受益;x64dbg也有局限,这时可以结合IDA,将IDA分析的结果导出Map供x64dbg使用,可以看到x64dbg分析不出的一些信息,比如一些高级语言的函数,这也是事半功倍的;分析过程中及时做好代码注释,以前过分相信自己的记忆,分析过程中只看不记,总觉得回头看到就能想起,现实是随着年老色衰,往往是几秒前问候过的代码都觉得陌生,尤其是Call进去后的第一行代码注释,往往很多地方调用,来来回回翻看很不方便,如果有注释点击Call进去看就知道这段代码的功能了。
    以下是注册算法的主要部分:
[Asm] 纯文本查看 复制代码
0045C61D        lea edx,dword ptr ss:[ebp-0x48]        
0045C620        mov eax,dword ptr ss:[ebp-0x4]        用户名"lies2022"
0045C623        call <reg.sub_45BE3C>        计算用户名MD5(32)
0045C628        lea eax,dword ptr ss:[ebp-0x48]        前一个Call返回的MD5
0045C62B        lea edx,dword ptr ss:[ebp-0x1C]        
0045C62E        call reg.45BEB0        MD5转字符串
0045C633        lea edx,dword ptr ss:[ebp-0x48]        "f3b715cab9553c8aaff743c61562a308"
0045C636        mov eax,dword ptr ss:[ebp-0x8]        到期时间"110512"
0045C639        call <reg.sub_45BE3C>        到期时间MD5
0045C63E        lea eax,dword ptr ss:[ebp-0x48]        前一个Call返回的MD5
0045C641        lea edx,dword ptr ss:[ebp-0x20]        
0045C644        call reg.45BEB0        MD5转字符串
0045C649        lea eax,dword ptr ss:[ebp-0x4C]        "316a6f4ced05edfc00f35e2699f0b762"
0045C64C        mov ecx,dword ptr ss:[ebp-0x20]        
0045C64F        mov edx,dword ptr ss:[ebp-0x1C]        
0045C652        call <reg.@System@@LStrCat3$qqrv>        前两个MD5字符串合并
0045C657        mov eax,dword ptr ss:[ebp-0x4C]        "f3b715cab9553c8aaff743c61562a308316a6f4ced05edfc00f35e2699f0b762"
0045C65A        lea edx,dword ptr ss:[ebp-0x48]        
0045C65D        call <reg.sub_45BE3C>        合并串MD5
0045C662        lea eax,dword ptr ss:[ebp-0x48]        
0045C665        lea edx,dword ptr ss:[ebp-0x18]        
0045C668        call reg.45BEB0        合并串MD5转字符串
0045C66D        lea eax,dword ptr ss:[ebp-0x10]        "45a5199feb18a39980fe17a5da4dad98"
0045C670        mov edx,dword ptr ss:[ebp-0x8]        
0045C673        call <reg.@System@@LStrLAsg$qqrpvpxv>        
0045C678        lea eax,dword ptr ss:[ebp-0x50]        
0045C67B        push eax        
0045C67C        mov ecx,0x2        取2位
0045C681        mov edx,0x1        从第1位开始
0045C686        mov eax,dword ptr ss:[ebp-0x10]        "110512"
0045C689        call <reg.Delphi_Copy_404880>        从第1位开始取2位
0045C68E        mov eax,dword ptr ss:[ebp-0x50]        
0045C691        call <reg.Delphi_StrToInt_408528>        字符串转整数
0045C696        mov ebx,eax        ebx=11
0045C698        lea eax,dword ptr ss:[ebp-0x54]        
0045C69B        push eax        
0045C69C        mov ecx,0x2        
0045C6A1        mov edx,0x3        
0045C6A6        mov eax,dword ptr ss:[ebp-0x10]        
0045C6A9        call <reg.Delphi_Copy_404880>        
0045C6AE        mov eax,dword ptr ss:[ebp-0x54]        
0045C6B1        call <reg.Delphi_StrToInt_408528>        
0045C6B6        mov esi,eax        esi=5
0045C6B8        lea eax,dword ptr ss:[ebp-0x58]        
0045C6BB        push eax        
0045C6BC        mov ecx,0x2        
0045C6C1        mov edx,0x5        
0045C6C6        mov eax,dword ptr ss:[ebp-0x10]        
0045C6C9        call <reg.Delphi_Copy_404880>        
0045C6CE        mov eax,dword ptr ss:[ebp-0x58]        
0045C6D1        call <reg.Delphi_StrToInt_408528>        
0045C6D6        mov edi,eax        edi=12
0045C6D8        lea eax,dword ptr ss:[ebp-0x5C]        
0045C6DB        push eax        
0045C6DC        lea edx,dword ptr ss:[ebp-0x60]        
0045C6DF        mov eax,ebx        11
0045C6E1        call reg.45C044        转二进制
0045C6E6        mov eax,dword ptr ss:[ebp-0x60]        "00001011"
0045C6E9        mov ecx,0x7        
0045C6EE        mov edx,0x2        
0045C6F3        call <reg.Delphi_Copy_404880>        第2位开始取7位
0045C6F8        push dword ptr ss:[ebp-0x5C]        "0001011"
0045C6FB        lea eax,dword ptr ss:[ebp-0x64]        
0045C6FE        push eax        
0045C6FF        lea edx,dword ptr ss:[ebp-0x68]        
0045C702        mov eax,esi        5
0045C704        call reg.45C044        转二进制
0045C709        mov eax,dword ptr ss:[ebp-0x68]        "00000101"
0045C70C        mov ecx,0x4        
0045C711        mov edx,0x5        
0045C716        call <reg.Delphi_Copy_404880>        第5位开始取4位
0045C71B        push dword ptr ss:[ebp-0x64]        "0101"
0045C71E        lea eax,dword ptr ss:[ebp-0x6C]        
0045C721        push eax        
0045C722        lea edx,dword ptr ss:[ebp-0x70]        
0045C725        mov eax,edi        12
0045C727        call reg.45C044        转二进制
0045C72C        mov eax,dword ptr ss:[ebp-0x70]        "00001100"
0045C72F        mov ecx,0x5        
0045C734        mov edx,0x4        
0045C739        call <reg.Delphi_Copy_404880>        第4位开始取5位
0045C73E        push dword ptr ss:[ebp-0x6C]        "01100"
0045C741        lea eax,dword ptr ss:[ebp-0x14]        
0045C744        mov edx,0x3        
0045C749        call <reg.@System@@LStrCatN$qqrv>        上面三个串合并"0001011010101100"
0045C74E        lea eax,dword ptr ss:[ebp-0x7C]        
0045C751        mov edx,dword ptr ss:[ebp-0x14]        
0045C754        mov dl,byte ptr ds:[edx+0x2]        
0045C757        mov byte ptr ds:[eax+0x1],dl        
0045C75A        mov byte ptr ds:[eax],0x1        二进制串取第3位ASCII,前面插入1(0130)
0045C75D        lea edx,dword ptr ss:[ebp-0x7C]        ^低位1表示长度
0045C760        lea eax,dword ptr ss:[ebp-0x80]        
0045C763        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C768        lea eax,dword ptr ss:[ebp-0x84]        
0045C76E        mov edx,dword ptr ss:[ebp-0x14]        
0045C771        mov dl,byte ptr ds:[edx+0x3]        
0045C774        mov byte ptr ds:[eax+0x1],dl        
0045C777        mov byte ptr ds:[eax],0x1        二进制串取第4位ASCII,前面插入1(0131)
0045C77A        lea edx,dword ptr ss:[ebp-0x84]        
0045C780        lea eax,dword ptr ss:[ebp-0x80]        
0045C783        mov cl,0x2        
0045C785        call <reg.@System@@PStrNCat$qqrv>        合并上面两串(023031)
0045C78A        lea edx,dword ptr ss:[ebp-0x80]        ^第1位2表示长度
0045C78D        lea eax,dword ptr ss:[ebp-0x88]        
0045C793        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C798        lea eax,dword ptr ss:[ebp-0x84]        
0045C79E        mov edx,dword ptr ss:[ebp-0x14]        
0045C7A1        mov dl,byte ptr ds:[edx+0x4]        
0045C7A4        mov byte ptr ds:[eax+0x1],dl        二进制串取第5位ASCII,前面插入1(0130)
0045C7A7        mov byte ptr ds:[eax],0x1        
0045C7AA        lea edx,dword ptr ss:[ebp-0x84]        
0045C7B0        lea eax,dword ptr ss:[ebp-0x88]        
0045C7B6        mov cl,0x3        
0045C7B8        call <reg.@System@@PStrNCat$qqrv>        
0045C7BD        lea edx,dword ptr ss:[ebp-0x88]        
0045C7C3        lea eax,dword ptr ss:[ebp-0x90]        
0045C7C9        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C7CE        lea eax,dword ptr ss:[ebp-0x84]        
0045C7D4        mov edx,dword ptr ss:[ebp-0x14]        
0045C7D7        mov dl,byte ptr ds:[edx+0x8]        二进制串第9位
0045C7DA        mov byte ptr ds:[eax+0x1],dl        
0045C7DD        mov byte ptr ds:[eax],0x1        
0045C7E0        lea edx,dword ptr ss:[ebp-0x84]        
0045C7E6        lea eax,dword ptr ss:[ebp-0x90]        
0045C7EC        mov cl,0x4        
0045C7EE        call <reg.@System@@PStrNCat$qqrv>        
0045C7F3        lea edx,dword ptr ss:[ebp-0x90]        
0045C7F9        lea eax,dword ptr ss:[ebp-0x98]        
0045C7FF        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C804        lea eax,dword ptr ss:[ebp-0x84]        
0045C80A        mov edx,dword ptr ss:[ebp-0x14]        
0045C80D        mov dl,byte ptr ds:[edx+0x9]        二进制串第10位
0045C810        mov byte ptr ds:[eax+0x1],dl        
0045C813        mov byte ptr ds:[eax],0x1        
0045C816        lea edx,dword ptr ss:[ebp-0x84]        
0045C81C        lea eax,dword ptr ss:[ebp-0x98]        
0045C822        mov cl,0x5        
0045C824        call <reg.@System@@PStrNCat$qqrv>        
0045C829        lea edx,dword ptr ss:[ebp-0x98]        
0045C82F        lea eax,dword ptr ss:[ebp-0xA0]        
0045C835        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C83A        lea eax,dword ptr ss:[ebp-0x84]        
0045C840        mov edx,dword ptr ss:[ebp-0x14]        
0045C843        mov dl,byte ptr ds:[edx+0xC]        二进制串第13位
0045C846        mov byte ptr ds:[eax+0x1],dl        
0045C849        mov byte ptr ds:[eax],0x1        
0045C84C        lea edx,dword ptr ss:[ebp-0x84]        
0045C852        lea eax,dword ptr ss:[ebp-0xA0]        
0045C858        mov cl,0x6        
0045C85A        call <reg.@System@@PStrNCat$qqrv>        
0045C85F        lea edx,dword ptr ss:[ebp-0xA0]        
0045C865        lea eax,dword ptr ss:[ebp-0xA8]        
0045C86B        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C870        lea eax,dword ptr ss:[ebp-0x84]        
0045C876        mov edx,dword ptr ss:[ebp-0x14]        
0045C879        mov dl,byte ptr ds:[edx+0xD]        二进制串第14位
0045C87C        mov byte ptr ds:[eax+0x1],dl        
0045C87F        mov byte ptr ds:[eax],0x1        
0045C882        lea edx,dword ptr ss:[ebp-0x84]        
0045C888        lea eax,dword ptr ss:[ebp-0xA8]        
0045C88E        mov cl,0x7        
0045C890        call <reg.@System@@PStrNCat$qqrv>        
0045C895        lea edx,dword ptr ss:[ebp-0xA8]        
0045C89B        lea eax,dword ptr ss:[ebp-0xB4]        
0045C8A1        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C8A6        lea eax,dword ptr ss:[ebp-0x84]        
0045C8AC        mov edx,dword ptr ss:[ebp-0x14]        
0045C8AF        mov dl,byte ptr ds:[edx+0xE]        二进制串第15位
0045C8B2        mov byte ptr ds:[eax+0x1],dl        
0045C8B5        mov byte ptr ds:[eax],0x1        
0045C8B8        lea edx,dword ptr ss:[ebp-0x84]        
0045C8BE        lea eax,dword ptr ss:[ebp-0xB4]        
0045C8C4        mov cl,0x8        
0045C8C6        call <reg.@System@@PStrNCat$qqrv>        上面8位合并"01010110"
0045C8CB        lea edx,dword ptr ss:[ebp-0xB4]        带长度的"01010110"
0045C8D1        lea eax,dword ptr ss:[ebp-0x78]        
0045C8D4        call <reg.unknown_libname_76>        LStrFromPCharLen
0045C8D9        mov eax,dword ptr ss:[ebp-0x78]        "01010110"
0045C8DC        call <reg.sub_45BF94>        循环读取二进制串,遇1则将剩余循环次数n做1<<n,结果累加
0045C8E1        lea ecx,dword ptr ss:[ebp-0x74]        0x56
0045C8E4        mov edx,0x2        
0045C8E9        call <reg.@Sysutils@IntToHex$qqrii>        
0045C8EE        mov eax,dword ptr ss:[ebp-0x74]        "56"
0045C8F1        push eax        
0045C8F2        lea eax,dword ptr ss:[ebp-0x7C]        
0045C8F5        mov edx,dword ptr ss:[ebp-0x14]        "0001011010101100"
0045C8F8        mov dl,byte ptr ds:[edx]        
0045C8FA        mov byte ptr ds:[eax+0x1],dl        二进制串第1位(30)
0045C8FD        mov byte ptr ds:[eax],0x1        长度1
0045C900        lea edx,dword ptr ss:[ebp-0x7C]        
0045C903        lea eax,dword ptr ss:[ebp-0x80]        
0045C906        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C90B        lea eax,dword ptr ss:[ebp-0x84]        
0045C911        mov edx,dword ptr ss:[ebp-0x14]        
0045C914        mov dl,byte ptr ds:[edx+0x1]        
0045C917        mov byte ptr ds:[eax+0x1],dl        二进制串第2位(30)
0045C91A        mov byte ptr ds:[eax],0x1        
0045C91D        lea edx,dword ptr ss:[ebp-0x84]        
0045C923        lea eax,dword ptr ss:[ebp-0x80]        
0045C926        mov cl,0x2        
0045C928        call <reg.@System@@PStrNCat$qqrv>        合并上面两串(023031)
0045C92D        lea edx,dword ptr ss:[ebp-0x80]        ^第1位2表示长度
0045C930        lea eax,dword ptr ss:[ebp-0x88]        
0045C936        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C93B        lea eax,dword ptr ss:[ebp-0x84]        
0045C941        mov edx,dword ptr ss:[ebp-0x14]        
0045C944        mov dl,byte ptr ds:[edx+0x5]        
0045C947        mov byte ptr ds:[eax+0x1],dl        二进制串第6位(31)
0045C94A        mov byte ptr ds:[eax],0x1        
0045C94D        lea edx,dword ptr ss:[ebp-0x84]        
0045C953        lea eax,dword ptr ss:[ebp-0x88]        
0045C959        mov cl,0x3        
0045C95B        call <reg.@System@@PStrNCat$qqrv>        
0045C960        lea edx,dword ptr ss:[ebp-0x88]        
0045C966        lea eax,dword ptr ss:[ebp-0x90]        
0045C96C        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C971        lea eax,dword ptr ss:[ebp-0x84]        
0045C977        mov edx,dword ptr ss:[ebp-0x14]        
0045C97A        mov dl,byte ptr ds:[edx+0x6]        
0045C97D        mov byte ptr ds:[eax+0x1],dl        二进制串第7位(31)
0045C980        mov byte ptr ds:[eax],0x1        
0045C983        lea edx,dword ptr ss:[ebp-0x84]        
0045C989        lea eax,dword ptr ss:[ebp-0x90]        
0045C98F        mov cl,0x4        
0045C991        call <reg.@System@@PStrNCat$qqrv>        
0045C996        lea edx,dword ptr ss:[ebp-0x90]        
0045C99C        lea eax,dword ptr ss:[ebp-0x98]        
0045C9A2        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C9A7        lea eax,dword ptr ss:[ebp-0x84]        
0045C9AD        mov edx,dword ptr ss:[ebp-0x14]        
0045C9B0        mov dl,byte ptr ds:[edx+0x7]        
0045C9B3        mov byte ptr ds:[eax+0x1],dl        二进制串第8位(30)
0045C9B6        mov byte ptr ds:[eax],0x1        
0045C9B9        lea edx,dword ptr ss:[ebp-0x84]        
0045C9BF        lea eax,dword ptr ss:[ebp-0x98]        
0045C9C5        mov cl,0x5        
0045C9C7        call <reg.@System@@PStrNCat$qqrv>        
0045C9CC        lea edx,dword ptr ss:[ebp-0x98]        
0045C9D2        lea eax,dword ptr ss:[ebp-0xA0]        
0045C9D8        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045C9DD        lea eax,dword ptr ss:[ebp-0x84]        
0045C9E3        mov edx,dword ptr ss:[ebp-0x14]        
0045C9E6        mov dl,byte ptr ds:[edx+0xA]        
0045C9E9        mov byte ptr ds:[eax+0x1],dl        二进制串第11位(31)
0045C9EC        mov byte ptr ds:[eax],0x1        
0045C9EF        lea edx,dword ptr ss:[ebp-0x84]        
0045C9F5        lea eax,dword ptr ss:[ebp-0xA0]        
0045C9FB        mov cl,0x6        
0045C9FD        call <reg.@System@@PStrNCat$qqrv>        
0045CA02        lea edx,dword ptr ss:[ebp-0xA0]        
0045CA08        lea eax,dword ptr ss:[ebp-0xA8]        
0045CA0E        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045CA13        lea eax,dword ptr ss:[ebp-0x84]        
0045CA19        mov edx,dword ptr ss:[ebp-0x14]        
0045CA1C        mov dl,byte ptr ds:[edx+0xB]        
0045CA1F        mov byte ptr ds:[eax+0x1],dl        二进制串第12位(30)
0045CA22        mov byte ptr ds:[eax],0x1        
0045CA25        lea edx,dword ptr ss:[ebp-0x84]        
0045CA2B        lea eax,dword ptr ss:[ebp-0xA8]        
0045CA31        mov cl,0x7        
0045CA33        call <reg.@System@@PStrNCat$qqrv>        
0045CA38        lea edx,dword ptr ss:[ebp-0xA8]        
0045CA3E        lea eax,dword ptr ss:[ebp-0xB4]        
0045CA44        call <reg.@System@@PStrCpy$qqrp28System@%SmallString$iuc$255%t1>        
0045CA49        lea eax,dword ptr ss:[ebp-0x84]        
0045CA4F        mov edx,dword ptr ss:[ebp-0x14]        
0045CA52        mov dl,byte ptr ds:[edx+0xF]        
0045CA55        mov byte ptr ds:[eax+0x1],dl        二进制串第16位(30)
0045CA58        mov byte ptr ds:[eax],0x1        
0045CA5B        lea edx,dword ptr ss:[ebp-0x84]        
0045CA61        lea eax,dword ptr ss:[ebp-0xB4]        
0045CA67        mov cl,0x8        
0045CA69        call <reg.@System@@PStrNCat$qqrv>        上面8位合并"00110100"
0045CA6E        lea edx,dword ptr ss:[ebp-0xB4]        带长度的"00110100"
0045CA74        lea eax,dword ptr ss:[ebp-0xBC]        
0045CA7A        call <reg.unknown_libname_76>        
0045CA7F        mov eax,dword ptr ss:[ebp-0xBC]        "00110100"
0045CA85        call <reg.sub_45BF94>        循环读取二进制串,遇1则将剩余循环次数n做1<<n,结果累加
0045CA8A        lea ecx,dword ptr ss:[ebp-0xB8]        0x34
0045CA90        mov edx,0x2        
0045CA95        call <reg.@Sysutils@IntToHex$qqrii>        
0045CA9A        mov edx,dword ptr ss:[ebp-0xB8]        "34"
0045CAA0        lea eax,dword ptr ss:[ebp-0x24]        
0045CAA3        pop ecx        "56"上一次结果
0045CAA4        call <reg.@System@@LStrCat3$qqrv>        两串合并"3456"
0045CAA9        lea eax,dword ptr ss:[ebp-0xC0]        
0045CAAF        mov ecx,dword ptr ss:[ebp-0x1C]        "f3b715cab9553c8aaff743c61562a308"用户名MD5
0045CAB2        mov edx,dword ptr ss:[ebp-0x24]        "3456"
0045CAB5        call <reg.@System@@LStrCat3$qqrv>        
0045CABA        mov eax,dword ptr ss:[ebp-0xC0]        "3456f3b715cab9553c8aaff743c61562a308"
0045CAC0        lea edx,dword ptr ss:[ebp-0x28]        
0045CAC3        call <reg.sub_45C244>        将eax按位读取,与dl最后1位亦或为1则(dl^0x18)>>1||0x80,为0则dl>>1(dl初始0),结果转为16进制字符串"EA"
0045CAC8        lea eax,dword ptr ss:[ebp-0x2C]        
0045CACB        push eax        
0045CACC        lea eax,dword ptr ss:[ebp-0xC8]        
0045CAD2        mov ecx,dword ptr ss:[ebp-0x28]        上个Call结果"EA"
0045CAD5        mov edx,dword ptr ss:[ebp-0x24]        "3456"
0045CAD8        call <reg.@System@@LStrCat3$qqrv>        "3456"+"EA"
0045CADD        mov eax,dword ptr ss:[ebp-0xC8]        "3456EA"
0045CAE3        lea edx,dword ptr ss:[ebp-0x48]        
0045CAE6        call <reg.sub_45BE3C>        MD5(32)
0045CAEB        lea eax,dword ptr ss:[ebp-0x48]        
0045CAEE        lea edx,dword ptr ss:[ebp-0xC4]        
0045CAF4        call reg.45BEB0        MD5转字符串
0045CAF9        mov eax,dword ptr ss:[ebp-0xC4]        "6189a4059d33687fea8dfe485d4e07c8"
0045CAFF        mov ecx,0x2        
0045CB04        mov edx,0x8        
0045CB09        call <reg.Delphi_Copy_404880>        第8位开始取2位"59"
0045CB0E        lea eax,dword ptr ss:[ebp-0xCC]        
0045CB14        mov ecx,dword ptr ss:[ebp-0x18]        "45a5199feb18a39980fe17a5da4dad98"合并串MD5
0045CB17        mov edx,dword ptr ss:[ebp-0x1C]        "f3b715cab9553c8aaff743c61562a308"用户名MD5
0045CB1A        call <reg.@System@@LStrCat3$qqrv>        合并前面2字符串
0045CB1F        mov eax,dword ptr ss:[ebp-0xCC]        "f3b715cab9553c8aaff743c61562a30845a5199feb18a39980fe17a5da4dad98"
0045CB25        lea edx,dword ptr ss:[ebp-0x30]        
0045CB28        call <reg.sub_45C244>        将eax按位读取,与dl最后1位亦或为1则(dl^0x18)>>1||0x80,为0则dl>>1(dl初始0),结果转为16进制字符串"6E"
0045CB2D        lea eax,dword ptr ss:[ebp-0xD0]        
0045CB33        mov ecx,dword ptr ss:[ebp-0x18]        "45a5199feb18a39980fe17a5da4dad98"合并串MD5
0045CB36        mov edx,dword ptr ss:[ebp-0x20]        "316a6f4ced05edfc00f35e2699f0b762"到期时间MD5
0045CB39        call <reg.@System@@LStrCat3$qqrv>        
0045CB3E        mov eax,dword ptr ss:[ebp-0xD0]        "316a6f4ced05edfc00f35e2699f0b76245a5199feb18a39980fe17a5da4dad98"
0045CB44        lea edx,dword ptr ss:[ebp-0x34]        
0045CB47        call <reg.sub_45C244>        将eax按位读取,与dl最后1位亦或为1则(dl^0x18)>>1||0x80,为0则dl>>1(dl初始0),结果转为16进制字符串"30"
0045CB4C        push dword ptr ss:[ebp-0x28]        
0045CB4F        push dword ptr ss:[ebp-0x24]        
0045CB52        push dword ptr ss:[ebp-0x2C]        
0045CB55        lea eax,dword ptr ss:[ebp-0xD8]        
0045CB5B        mov edx,dword ptr ss:[ebp-0x18]        "45a5199feb18a39980fe17a5da4dad98"
0045CB5E        mov dl,byte ptr ds:[edx+0x7]        从第8位开始取1位(取第8位)
0045CB61        call <reg.unknown_libname_73>        LStrFromPCharLen取1位
0045CB66        push dword ptr ss:[ebp-0xD8]        "f"
0045CB6C        lea eax,dword ptr ss:[ebp-0xDC]        
0045CB72        mov edx,dword ptr ss:[ebp-0x18]        
0045CB75        mov dl,byte ptr ds:[edx+0xE]        取第16位
0045CB78        call <reg.unknown_libname_73>        
0045CB7D        push dword ptr ss:[ebp-0xDC]        "9"
0045CB83        push dword ptr ss:[ebp-0x30]        
0045CB86        lea eax,dword ptr ss:[ebp-0xE0]        
0045CB8C        mov edx,dword ptr ss:[ebp-0x18]        
0045CB8F        mov dl,byte ptr ds:[edx+0x17]        取第24位
0045CB92        call <reg.unknown_libname_73>        
0045CB97        push dword ptr ss:[ebp-0xE0]        "5"
0045CB9D        lea eax,dword ptr ss:[ebp-0xE4]        
0045CBA3        mov edx,dword ptr ss:[ebp-0x18]        
0045CBA6        mov dl,byte ptr ds:[edx+0xB]        取第12位
0045CBA9        call <reg.unknown_libname_73>        
0045CBAE        push dword ptr ss:[ebp-0xE4]        "8"
0045CBB4        push dword ptr ss:[ebp-0x34]        "30"来自0045CB47
0045CBB7        lea eax,dword ptr ss:[ebp-0xD4]        
0045CBBD        mov edx,0x9        9:'\t'
0045CBC2        call <reg.@System@@LStrCatN$qqrv>        将上面数个字符连接,Call后出现真码
0045CBC7        mov eax,dword ptr ss:[ebp-0xD4]        "EA345659f96E5830"
0045CBCD        lea edx,dword ptr ss:[ebp-0x38]        
0045CBD0        call <reg.@Sysutils@UpperCase$qqrx17System@AnsiString>        转换成大写
0045CBD5        mov eax,dword ptr ss:[ebp-0xC]        
0045CBD8        mov edx,dword ptr ss:[ebp-0x38]        "EA345659F96E5830"真码

    0045C62 call <reg.sub_45BE3C>这个调用是计算MD5的,实际上我并未跟进去,只是动态调试的时候看着像是MD5,用工具验证了一下确实结果一样,所以之前就说过动态调试的重要性,这些算法给源代码我都未必能看懂,何况是反汇编,如果硬磕估计会影响某些功能。
    注册算法中0045C67C-0045CAA4之间的代码尽管很长,其实就是用有效期算出一个4位字符串,而有效期是一个固定的“110512”,因此这个结果字符串也是固定的“3456”,我们在最后写注册机的时候直接使用即可,不必复现计算过程。这部分Call里面我就不详细的说明了,Call的作用我已经在代码后面注明,感兴趣的可以自己跟进去看一下。
    CrackMe是用Delphi编写的,IDA已经分析出了一些函数名,函数具体功能可以在网络上很方便的查到。
    0045CAC call <reg.sub_45C244>是对输入串做计算,输出一个2位字符串,算法如下:
[Asm] 纯文本查看 复制代码
0045C274        mov eax,dword ptr ss:[ebp-0x4]        "3456f3b715cab9553c8aaff743c61562a308"
0045C277        call <reg.unknown_libname_78>        取长度0x24
0045C27C        and eax,0x80000001        结果0
0045C281        jns reg.45C288        
0045C283        dec eax        
0045C284        or eax,0xFFFFFFFE        
0045C287        inc eax        
0045C288        dec eax        结果-1
0045C289        jne reg.45C298        
0045C28B        lea eax,dword ptr ss:[ebp-0x4]        
0045C28E        mov edx,reg.45C360        45C360:L"0"
0045C293        call <reg.@System@@LStrCat$qqrv>        
0045C298        mov eax,dword ptr ss:[ebp-0x4]        "3456f3b715cab9553c8aaff743c61562a308"
0045C29B        call <reg.unknown_libname_78>        取长度0x24
0045C2A0        mov esi,eax        
0045C2A2        sar esi,0x1        结果0x12
0045C2A4        jns reg.45C2A9        
0045C2A6        adc esi,0x0        
0045C2A9        test esi,esi        
0045C2AB        jle reg.45C2F2        
0045C2AD        mov edi,0x1        
0045C2B2        lea ebx,dword ptr ss:[ebp-0x108]        
0045C2B8        push 0x1F4        
0045C2BD        lea eax,dword ptr ss:[ebp-0x10C]        
0045C2C3        push eax        
0045C2C4        mov eax,edi        
0045C2C6        dec eax        
0045C2C7        mov edx,eax        
0045C2C9        add edx,edx        
0045C2CB        inc edx        
0045C2CC        mov ecx,0x2        
0045C2D1        mov eax,dword ptr ss:[ebp-0x4]        "3456f3b715cab9553c8aaff743c61562a308"
0045C2D4        call <reg.Delphi_Copy_404880>        从edx位取2位
0045C2D9        mov eax,dword ptr ss:[ebp-0x10C]        取出的2位
0045C2DF        xor ecx,ecx        
0045C2E1        mov edx,0x10        
0045C2E6        call <reg.sub_45C118>        StrToInt
0045C2EB        mov byte ptr ds:[ebx],al        
0045C2ED        inc edi        
0045C2EE        inc ebx        
0045C2EF        dec esi        
0045C2F0        jne reg.45C2B8        以上循环将字符串转为数字
0045C2F2        mov eax,dword ptr ss:[ebp-0x4]        "3456f3b715cab9553c8aaff743c61562a308"
0045C2F5        call <reg.unknown_libname_78>        取长度0x24
0045C2FA        sar eax,0x1        
0045C2FC        jns reg.45C301        
0045C2FE        adc eax,0x0        
0045C301        lea edx,dword ptr ss:[ebp-0x108]        0x3456f3b715cab9553c8aaff743c61562a308
0045C307        mov ecx,eax        
0045C309        mov eax,0xFF        
0045C30E        xchg edx,eax        
0045C30F        call reg.45C09C        将eax按位读取,与dl最后1位亦或为1则(dl^0x18)>>1||0x80(dl初始0)
0045C314        mov ebx,eax        
0045C316        mov ecx,dword ptr ss:[ebp-0x8]        
0045C319        xor eax,eax        
0045C31B        mov al,bl        
0045C31D        mov edx,0x2        
0045C322        call <reg.@Sysutils@IntToHex$qqrii>        将上面Call结果转为16进制字符串

    到这里涉及计算的部分就结束了,剩下的部分就是把前面的计算结果拼起来,生成16位字符串,最后转换成大写的序列号。
    最后写注册机,想起原来看到过一个aardio的国人开发的小巧的编程语言,早就想试试,就用他吧。于是花了半天时间学习了一下语法,敲下了总共三十行代码,边学边做平均五分钟一行的速度,是不是太笨了?不过出来的东西感觉还不错,是我喜欢的简洁明了。
    注册机代码:
[C] 纯文本查看 复制代码
function ToHex(src){
	var data = 0;
	len = string.len(src);
	for(i = 1; len; 2){
		one = tonumber('0x' + string.slice(src, i, i + 1,));
		for(j = 1; 8){
			if((((one >> (j - 1)) & 1) ^ (data & 1)) == 1){
				data = ((data ^ 0x18) >> 1) | 0x80;
			}
			else{
				data = data >> 1;
			}
		}	
	}
	return string.format("%02X",data);
}

mainForm.button.oncommand = function(id,event){
	if(mainForm.edit.text == ''){mainForm.edit2.text = '请输入用户名';}
	else{
	usermd5 = crypt.md5(mainForm.edit.text, 0);
	datemd5 = crypt.md5('110512', 0);
	catmd5 = crypt.md5(usermd5 + datemd5);
	Key = ToHex('3456' + usermd5);
	Key = Key + '3456' + string.slice(crypt.md5('3456' + Key), 8, 9) + string.slice(catmd5,8,8) +
	 string.slice(catmd5,15,15) + ToHex(usermd5 + catmd5) + string.slice(catmd5,24,24) +
	 string.slice(catmd5,12,12) + ToHex(datemd5 + catmd5);
	mainForm.edit2.text = Key;
	file = io.open('reg.dll', 'w');
	file.write('UserName=', mainForm.edit.text, '\n');
	file.write('SN=', Key, '\n');
	file.close(); 
	}
}

    编译好后,验证一下,注册机输入用户名,生成注册码后自动生成注册需要的reg.dll文件(其实就是个文本文件)。

    reg.dll复制到CrackMe同目录,运行CrackMe,大功告成!

    附件包含CrackMe及注册机。
007.rar (589.13 KB, 下载次数: 14)

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参与人数 2吾爱币 +8 热心值 +2 收起 理由
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推荐
Hmily 发表于 2022-10-12 16:30
搜了下关键词论坛好像不少这题的算法分析:

练习笔记之160Crackme-007
https://www.52pojie.cn/thread-1629880-1-1.html
160个crackme-007注册机编写
https://www.52pojie.cn/thread-1496557-1-1.html
160个Crackme007之分析思路和注册算法分析详解
https://www.52pojie.cn/thread-1131694-1-1.html
160 crackme 之 007
https://www.52pojie.cn/thread-1352537-1-1.html
探讨crackMe160之007中破解问题
https://www.52pojie.cn/thread-488516-1-1.html
推荐
 楼主| lies2014 发表于 2022-10-12 16:57 |楼主
Hmily 发表于 2022-10-12 16:30
搜了下关键词论坛好像不少这题的算法分析:

练习笔记之160Crackme-007

谢谢大大关注,新160个CrackMe是有人重新整理过的,换掉了原版160 CrackMe中的一些题目,这题就是被换掉的,和你链接里那些都不一样,应该本论坛没有人分析过,新160的题目来自这里:https://www.zhihu.com/people/wanao-meng-tian/zvideos

点评

论坛应该都是来自这里 【反汇编练习】160个CrackME索引目录1~160建议收藏备用 https://www.52pojie.cn/thread-709699-1-1.html  详情 回复 发表于 2022-10-12 16:59
4#
29565633 发表于 2022-10-7 15:47
5#
戰龍在野 发表于 2022-10-7 19:23
谢谢提供分享好好学习一下
6#
ABC9758 发表于 2022-10-8 23:00
谢谢分享,收藏备用
7#
Junlee 发表于 2022-10-9 01:13
学习了,受益匪浅
8#
七月上H 发表于 2022-10-9 08:22
学习了,很有帮助的
9#
syxf88888 发表于 2022-10-10 07:15
支持一下
10#
Hmily 发表于 2022-10-12 16:59
lies2014 发表于 2022-10-12 16:57
谢谢大大关注,新160个CrackMe是有人重新整理过的,换掉了原版160 CrackMe中的一些题目,这题就是被换掉 ...

论坛应该都是来自这里

【反汇编练习】160个CrackME索引目录1~160建议收藏备用
https://www.52pojie.cn/thread-709699-1-1.html
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