一个VB注册函数方法分析

moocher

注册码函数分析
机器号：279422942294  共12位
对应ASCII 32，37，39，34，32，32，39，34，32，32，39，34
生成序列号：32FK156637FK
有兴趣的朋友一起分析分析算法

[Visual Basic] 纯文本查看 复制代码

Private Sub Proc_2_42_83F890
  loc_0083F8E7: var_8004 = Len(Me)                  // 取机器码长度，开始循环【1~C】
  loc_0083F915: If 1 > var_8004 Then GoTo loc_0083FCC1  //长度为0跳出，循环1完毕跳出
  loc_0083F954: var_3C = CStr(Mid(var_74, 1, 1))          // 取第n位数转字符
  loc_0083F983: movzx dx, Asc(var_3C)                 // 取第n个字符的ASCII码
  loc_0083F99C: var_18 = (ecx - var_3C)                 // 
  loc_0083F9BC: If 1 > var_8004 Then GoTo loc_0083FAE2         // 长度为0跳转，循环2完毕跳出。
  loc_0083FA0B: var_24 = Asc(CStr(Mid(var_74, 1, 1)))                 // 取第n个字符的ASCII码
  loc_0083FA6D: var_3C = CStr(Mid(var_74, var_8004(1)(-1), 1)) // 取倒数第n个字符串
  loc_0083FA7D: var_2C = Asc(var_3C)              //字符对应的ASCII码
  loc_0083FAC5: ((ecx - var_3C) And 255) = ((ecx - var_3C) And 255) + var_2C*var_24*var_20*1  // ecx 应该是第n个数字，  倒数第n个*正数第n个*n*1 ,双循环
  loc_0083FADD: GoTo loc_0083F9B5
  loc_0083FAE2: ' Referenced from: 0083F9BC // 循环2结束
  loc_0083FAE9: If Sign((((ecx - var_3C) And 255)+var_2C*var_24*var_20*1 And &H800000FF) - 0) Then GoTo loc_0083FAF2
  loc_0083FAF2 : ' Referenced from: 0083FAE9
  loc_0083FAF5: If ((((ecx - var_3C) And 255)+var_2C*var_24*var_20*1 And &H800000FF) - 1 Or -256) + 1 <> 48 Then GoTo loc_0083FB02  //排除字符0
  loc_0083FB00: GoTo loc_0083FB20
  loc_0083FB02: ' Referenced from: 0083FAF5
  loc_0083FB05: If var_30 <> 79 Then GoTo loc_0083FB12// 排除大写的O
  loc_0083FB10: GoTo loc_0083FB20
  loc_0083FB12: ' Referenced from: 0083FB05
  loc_0083FB15: If var_30 <> 111 Then GoTo loc_0083FB36// 排除小写的o
  loc_0083FB20: ' Referenced from: 0083FB00
  loc_0083FB20: ' Referenced from: 0083FB10
  loc_0083FB2B: var_30 = var_30 & global_004725D8  // 0赋值1,O赋值2,o赋值3
  loc_0083FB31: GoTo loc_0083FCA7
  loc_0083FB39: If var_30 < 49 Then GoTo loc_0083FB90// 小于1
  loc_0083FB3E: If var_30 > 57 Then GoTo loc_0083FB90// 大于9，特殊字符
  loc_0083FB76: var_30 = var_30 & Chr(var_30)// 1到9数字的运算法则
  loc_0083FB8B: GoTo loc_0083FCA7
  loc_0083FB90: ' Referenced from: 0083FB39
  loc_0083FB93: If eax < 65 Then GoTo loc_0083FB9A// 小于A，特殊字符
  loc_0083FB98: If eax <= 78 Then GoTo loc_0083FBA4// A~N
  loc_0083FB9A: ' Referenced from: 0083FB93
  loc_0083FB9D: If eax < 80 Then GoTo loc_0083FBF4// 79 P
  loc_0083FBA2: If eax > 90 Then GoTo loc_0083FBF4// Z后的特殊字符
  loc_0083FBDA: var_30 = var_30 & Chr(0) //大写字符P及以前的运算法则
  loc_0083FBEF: GoTo loc_0083FCA7
  loc_0083FBF4: ' Referenced from: 0083FB9D
  loc_0083FBF7: If eax < 97 Then GoTo loc_0083FBFE// a前的特殊字符
  loc_0083FBFC: If eax <= 110 Then GoTo loc_0083FC08// a~n
  loc_0083FBFE: ' Referenced from: 0083FBF7
  loc_0083FC01: If eax < 112 Then GoTo loc_0083FC67 //111 p
  loc_0083FC06: If eax > 122 Then GoTo loc_0083FC67 //z以后的特殊字符
  loc_0083FC4C: var_30 = var_30 & Ucase(Chr(0)) //小写字符p及以前的的运算法则
  loc_0083FC65: GoTo loc_0083FCA7
  loc_0083FC67: ' Referenced from: 0083FC01 //特殊字符处理
  loc_0083FC73:  Mod 00000009h =  Mod 00000009h + 1
  loc_0083FC9C: var_30 = var_30 & CStr( Mod 00000009h+1)
  loc_0083FCA7: ' Referenced from: 0083FB31
  loc_0083FCA7: ' Referenced from: 0083FB8B
  loc_0083FCA7: ' Referenced from: 0083FBEF
  loc_0083FCA7: ' Referenced from: 0083FC65
  loc_0083FCB9: var_20 = 1+var_20 // 循环+1
  loc_0083FCBC: GoTo loc_0083F90E  // 返回循环1
  loc_0083FCC1: ' Referenced from: 0083F915 //运算结束跳转到这里
  loc_0083FCCE: If Len(var_30) >= 12 Then GoTo loc_0083FD1D  // 判断字符长度是否大于等于12
  loc_0083FD08: var_30 = Left(var_30 & "A1B2C3D4E5F6", 12) //超过后处理
  loc_0083FD1D: ' Referenced from: 0083FCCE
  loc_0083FD23: var_38 = var_30
  loc_0083FD2E: GoTo loc_0083FD60
  loc_0083FD34: If var_4 = 0 Then GoTo loc_0083FD3F
  loc_0083FD3F: ' Referenced from: 0083FD34
  loc_0083FD5F: Exit Sub
  loc_0083FD60: ' Referenced from: 0083FD2E
End Sub

约定的童话

VB能追出源码不？

moocher

[C] 纯文本查看 复制代码

#include <stdio.h>
#define MAX_DATA_LEN 12
char OriginData[MAX_DATA_LEN]= {'2','7','9','4','2','2','9','4','2','2','9','4'};//输入279422942294,输出32FK156637FK
char calcuData[MAX_DATA_LEN];     //calculated data
int DataTransfer(char *dataIn, char *dataOut)
{
    int i   = 0;
    char a1 = dataIn[0];
    char b1 = dataIn[11];
    char compleCode;              //c1, complement code
    int  asciiCode;
    for(i=0; i<MAX_DATA_LEN; i++)
    {
        compleCode = 0xff - dataIn[i];
        asciiCode  = b1 * a1 * (i+1) * 12 + compleCode;
        asciiCode  = asciiCode & 0xff;
	   //printf("%02x，compleCode;\n", compleCode);
       // printf("%02x，asciiCode;\n", asciiCode);
        if('0' == asciiCode)
        {
            dataOut[i] = '1';
        }
        else if('O' == asciiCode)
        {
            dataOut[i] = '2';
        }
        else if('o' == asciiCode)
        {
            dataOut[i] = '3';
        }
        else if(('1' <= asciiCode) && (asciiCode <= '9'))
        {
            dataOut[i] = asciiCode;
        }
        else if(('A' <= asciiCode) && (asciiCode <= 'Z'))
        {
            dataOut[i] = asciiCode;
        }
        else if(('a' <= asciiCode) && (asciiCode <= 'z'))
        {
            dataOut[i] = asciiCode + 'A' - 'a';
        }
        else
        {
            dataOut[i] = (asciiCode % 9) + 1 + '0';
        }

    }

    return 0;
}

int main(void)
{
    DataTransfer(OriginData, calcuData);
    printf(calcuData);
    return 0;
}