self.filesmi = {}
self.filesmi["1"] = 7654
self.filesmi["5"] = 6548
self.filesmi["7"] = 6755
self.filesmi["8"] = 4686
self.filesmi["11"] = 6765
self.filesmi["12"] = 6576
self.filesmi["13"] = 4353
self.filesmi["自用"] = 9879
local __wdf = require("script/资源类/WDF")
local format = string.format
local a = wdf配置--"WDF/"
self.id2file = {}
for n=1,#self.files do
-- if files[n] == "sound.wdf" or files[n] == "sound.wd1" then
-- a = "./"
-- end
self.wdf[self.files[n]] = __wdf(format("%s/%s",a,self.files[n]),self.filesmi[self.files[n]])
self.记录[self.files[n]]={}
end
__wdf = require("script/资源类/锦衣wdf")
以下是锦衣WDF
local Key = {
0x8E,0x38,0x8F,0x75,0x83,0xB7,0x43,0x0D,0xDD,0x88,0xAD,0x29,0x4C,0xF9,0xB4,0xE4,
0x44,0xF4,0xA3,0x64,0x7D,0x4B,0x5C,0x0B,0x34,0x09,0x12,0x5A,0x14,0xB4,0x98,0xB5,
0x85,0x55,0x61,0x0D,0x0A,0x12,0x62,0x61,0xE0,0x02,0x74,0x78,0x7A,0x19,0xC7,0x0B,
0x09,0xAC,0x94,0x30,0x60,0x46,0xE1,0xB3,0x02,0xB8,0xCC,0x4A,0xF7,0xD3,0x6B,0xAD,
0x49,0x63,0x76,0x83,0x6C,0xC1,0x8F,0x30,0xB0,0xB0,0x92,0xF3,0x3C,0x15,0xFE,0xF3,
0x0C,0x2A,0x1B,0x65,0x8C,0x98,0xE3,0xA5,0x92,0x1A,0x3A,0x05,0x2E,0x61,0xC0,0x63,
0x0B,0x55,0x60,0x4A,0x4C,0xC5,0x29,0x90,0x1E,0x64,0x8C,0xBA,0xDF,0xD7,0x4F,0xD7,
0xBB,0xB8,0xA6,0xB2,0x85,0xA5,0xC7,0xE9,0x7E,0x73,0x28,0xBF,0x75,0x8C,0xDE,0x5C,
0x28,0x5A,0xFE,0x31,0x11,0x7E,0x19,0x45,0x11,0x94,0xF4,0x9E,0x4C,0xE6,0x6E,0x58,
0x48,0x6F,0xC9,0xEC,0x36,0x61,0xBB,0x9C,0x03,0x57,0x67,0xF1,0x0C,0xC4,0x75,0xF7,
0xCA,0xAF,0x98,0x31,0xCF,0xD7,0xF8,0x1A,0x2F,0x35,0x14,0xDB,0x75,0x19,0x93,0x0F,
0xA4,0x83,0x27,0x7D,0x67,0x67,0x74,0x93,0x49,0x63,0x08,0x67,0xB1,0x54,0xEA,0xD7,
0xD9,0x34,0x03,0x0B,0x70,0x09,0xD9,0x33,0x85,0xA4,0x79,0x1F,0x57,0xA0,0x4B,0x88,
0x02,0x11,0x79,0x4F,0x8A,0x6E,0x0F,0x95,0xBF,0x08,0x5F,0x4F,0x74,0xAE,0x19,0xDA,
0xBB,0x80,0xC9,0x3A,0x3A,0x94,0xBA,0x11,0x18,0x46,0xFC,0x8C,0x33,0x48,0x0D,0x18,
0x10,0x5A,0xF1,0x9C,0x57,0xCF,0x2A,0xCB,0xB6,0x5D,0x3C,0x19,0x0B,0x3B,0xFC,0xDD,
0x20
}
local function _解密列表(Data, Size)
local Data = ffi.cast("char*", Data)
local Key_Step = 1
for i = 0, Size - 1, 1 do
Data[i] = bit.bxor(Data[i], Key[Key_Step])
Key_Step = Key_Step + 1
if Key_Step == 34 then
Key_Step = Key_Step + 1
end
if Key_Step == 258 then
Key_Step = 1
end
end
end
求大神解密以下 上面 1 5 8 这些文件的 密码
我有文件和解密软件 就是没有密码 源码里面这些应该就是解密公式 但是我不懂
GGELUA的源码里面的
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发表于 2021-6-24 12:51
