这个通过传参给结构体赋值的例子错在哪里了？【已解决】

jessylake

[C++] 纯文本查看 复制代码

using namespace std;

struct teacher
{
 int id;
 char name[64];
};



int get_mem(struct teacher** tpp)
{


 *tpp = (struct teacher *) malloc(sizeof(struct teacher));
 if (*tpp == NULL){
  return -1;
 }
 *tpp->id = 100;    //这句和下面那句为什么报错？上面不是指向结构体了吗？
 strcpy(*tpp->name, "mike");

 return 0;
}



void free_teacher(struct teacher **tpp)
{
 if (*tpp != NULL){
  free(*tpp);
  *tpp = NULL;
 }
}



int main()
{
 struct teacher *tp = NULL;

 get_mem(&tp);
 cout << "id=" << tp->id << " name=" << tp->name << endl;
 free_teacher1(&tp);


 return 0;
}

jessylake

终于知道，一疏忽把优先级给忘了
(*tpp)->id
因为->的优先级高于*

Try0oo

嗯嗯自己找出来的错误印象才深刻